if a city is located in latitude of 22.5 degrees, what is the speed in m/s of that city?

taking the radius of earth to be constant and something like 6340km,

speed of the city = (6340 cos(22.5 degrees))sq +(6340 sin(22.5)) sq km/day

think this is rite. sq = square of the no. inside the brackets

Assuming the earth to be perfectly spherical, the radius of the earth to be 6400 km and that the earth completes its one complete rotation in 24 hours, the speed of a city (in this case, I am considering city to be a point object) will be: 499.99m/s.

Wow! Thatýs so huge. Never thought it would be that high!
We wouldnýt feel it to be going at such high speed as the atmosphere is also moving with us. Its all relative thing.

Anyway, that was just my tryýmight be wrong too.

(I found the radius of the circle at 22.5 degrees to be (640000 Cos 22.5)m. And its simple after that.

correction: take the square root of the entire left hand side too in my above equation.

another: imeant the right hand side.

Typo: My answer should be 429.99m/s.

I already can see some flaw in your work passinthru, check it.

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what flaw, hawguji? R u manne, by any chance? :D saw the no. 266 hidden.

guys i havent solved it yet :P but the clue is linear velocity of the the city from the equator is 4000 miles..so figure it out..u all might be right..:) yah hawaguji u r right u need to use sin to figure out the distance...hence, i will give my best to solve the problem at night..ahile am going to wrk :)